Specific Process Knowledge/Etch/KOH Etch/ProcessInfo: Difference between revisions

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Nanolabs standard solution in the KOH baths has a concentration of 28 wt% and is mixed of 1 liter of a premade 50wt% KOH solution to 1.2 l of water.
Nanolabs standard solution in the KOH baths has a concentration of 28 wt% and is mixed of 1 liter of a premade 50wt% KOH solution to 1.2 l of water.
For 1 l of water you can calculate the required amount of KOH pills (X) to achieve the desired concentration in wt% (Y) by:





Revision as of 14:44, 7 September 2021

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QC

Quality Control (QC) for the KOH Si etching baths.

Quality Control (QC) for Si Etch 01, and Si Etch 02
QC Recipe:  
Solution 28 wt% KOH
Temperature 80°C
Time 90 min
Elevator On
Substrate Si (100)
Masking Thermal SiO2
QC limits Si Etch 1 Si Etch 2 Si Etch 3
Etch rate in Si(100) Latest QC Data on Si Etch 1 Info page (under Documents) Latest QC Data on Si Etch 2 Info page (under Documents) Latest QC Data on Si Etch 3 Info page (under Documents)
Roughness Only evaluated visually Only evaluated visually Only evaluated visually
Nonuniformity < 3% < 3% < 3%


Mixing KOH

Nanolabs standard solution in the KOH baths has a concentration of 28 wt% and is mixed of 1 liter of a premade 50wt% KOH solution to 1.2 l of water.


If you use the 50wt% premade KOH solution you can calculate the amount of solution X you need to add 1 liter of water to achieve a concentration of Y wt% by:


Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{(0.5\cdot 1.509g/ml\cdot X)}{(X\cdot 1.509g/ml+1000g)}=Y}


Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle X=\frac{(Y\cdot 1000g)}{(1.509g/ml\cdot(0.5-Y))}}


where 1.509 g/ml is the density of a 50wt% solution KOH at 20 °C.

So for a 10 wt% solution you will need 165 ml of KOH (50wt%) to 1 l of water.

Backside protection

It is possible to protect the backside of the wafer against the KOH etch using special wafer holder.

Theory

Definition of structures

Due to the almost inert (111)-planes it is possible by KOH etching to realize high aspect ratio structures in sigle crytalline silicon using the (111)-planes as sidewalls. In Si(100) these sidewalls are inclined - 54.7o with respect to the (100) surface - whereas in Si(110) the sidewalls are vertical (see figures below).


For Si(100), the relation between the width of the bottom of the etched groove (Wb) and the width of the opening (Wo) at the wafer surface in a groove etched to the depth l is given by:


Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle W_b = W_o - 2lcot(54.7^o) = W_o - \sqrt{2} l}



Definition of <110> alignment structures

The etch rate dependence on the crystallographic planes can be used to determine the <110> crystal directions with high precision (better than +/- 0.05 o). A fast method for doing this, using the symmetric under-etching behavior around but not at the <110>-directions, was described by Vangbo and Bäcklund in J. Micromech. Microeng.6 (1996), 279-284. High-precision control of the <110>-direction during alignment can be necessary in order to control the dimensions of KOH-etched structures (e.g. precise control of V-groove dimensions). A dedicated mask (MASK NAME) has been designed for this purpose.


Etch rates: Empirical formula (Seidl et al)

The following empirical formula can be used for concentrations in the range of 10-60 wt%:

R = k0 [H2O]4 [KOH]0.25 e-Ea/kT,

where k0 = 2480 µm/hr (mol/l)-4.25, Ea = 0.595 eV for Si(100)

and k0 = 4500 µm/hr (mol/l)-4.25, Ea = 0.60 eV for Si(110)