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DCH-Employees-701, NLAB-Employees-701, NLAB-LabmanagerAllUsers
1,146 edits
Kabi (talk | contribs)
DCH-Employees-701, NLAB-Employees-701, NLAB-LabmanagerAllUsers
1,146 edits
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For 1 l of water you can calculate the required amount of KOH pills (X) to achieve the desired concentration in wt% (Y) by:
For 1 l of water you can calculate the required amount of KOH pills (X) to achieve the desired concentration in wt% (Y) by:


(0.85 ∙X)/(X+1000g)=Y


<math> (0.85 ∙X)/(X+1000g)=Y</math>
X=(Y∙1000g)/(0.85-Y)
 
<math> X=(Y∙1000g)/(0.85-Y)</math>


So for a 10wt% solution you will need 133 g pills for each liter of water.
So for a 10wt% solution you will need 133 g pills for each liter of water.
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