Specific Process Knowledge/Etch/KOH Etch/ProcessInfo: Difference between revisions
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For 1 l of water you can calculate the required amount of KOH pills (X) to achieve the desired concentration in wt% (Y) by: | For 1 l of water you can calculate the required amount of KOH pills (X) to achieve the desired concentration in wt% (Y) by: | ||
(0.85 ∙X)/(X+1000g)=Y | (0.85 ∙X)/(X+1000g)=Y | ||
X=(Y∙1000g)/(0.85-Y) | X=(Y∙1000g)/(0.85-Y) | ||
So for a 10wt% solution you will need 133 g pills for each liter of water. | So for a 10wt% solution you will need 133 g pills for each liter of water. | ||
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If you use the 50wt% premade solution you can calculate the amount of solution X you need to add 1 liter of water to achieve a concentration of Y wt% by: | If you use the 50wt% premade solution you can calculate the amount of solution X you need to add 1 liter of water to achieve a concentration of Y wt% by: | ||
(0.5∙1.509 g/ml ∙X)/(X∙1.509 g/ml+1000g)=Y | (0.5∙1.509 g/ml ∙X)/(X∙1.509 g/ml+1000g)=Y | ||
X=(Y∙1000g)/(1.509 g/ml∙(0.5-Y)) | X=(Y∙1000g)/(1.509 g/ml∙(0.5-Y)) | ||
where 1.509 g/ml is the density of a 50wt% solution KOH at 20 °C. | where 1.509 g/ml is the density of a 50wt% solution KOH at 20 °C. | ||