Jump to content

Specific Process Knowledge/Etch/KOH Etch/ProcessInfo: Difference between revisions

Kabi (talk | contribs)
No edit summary
Mbec (talk | contribs)
 
(2 intermediate revisions by one other user not shown)
Line 1: Line 1:
'''Feedback to this page''': '''[mailto:labadviser@danchip.dtu.dk?Subject=Feed%20back%20from%20page%20http://labadviser.danchip.dtu.dk/index.php/Specific_Process_Knowledge/Etch/KOH_Etch/ProcessInfo click here]'''
'''Feedback to this page''': '''[mailto:labadviser@danchip.dtu.dk?Subject=Feed%20back%20from%20page%20http://labadviser.danchip.dtu.dk/index.php/Specific_Process_Knowledge/Etch/KOH_Etch/ProcessInfo click here]'''


''Unless anything else is stated, everything on this page, text and pictures are made by DTU Nanolab.''
'''Unless anything else is stated, everything on this page, text and pictures are made by DTU Nanolab.'''
 
'''All links to Kemibrug (SDS) and Labmanager Including APV and QC requires login.'''
 


==QC==
==QC==
===Quality Control (QC) for the KOH Si etching baths.===
===Quality Control (QC) for the KOH Si etching baths.===
''All links in the table below reguire login to labmanager**
'''All links in the table below reguire login to labmanager'''
{| border="1" cellspacing="2" cellpadding="2" colspan="3"
{| border="1" cellspacing="2" cellpadding="2" colspan="3"
|bgcolor="#98FB98" |'''Quality Control (QC) for Si Etch 01, and Si Etch 02'''
|bgcolor="#98FB98" |'''Quality Control (QC) for Si Etch 01, and Si Etch 02'''
Line 13: Line 16:
*[http://labmanager.dtu.dk/d4Show.php?id=5476&mach=407 The QC procedure for Si Etch: 03]<br>
*[http://labmanager.dtu.dk/d4Show.php?id=5476&mach=407 The QC procedure for Si Etch: 03]<br>
{| {{table}}
{| {{table}}
| align="center" |  
| align="center" |
{| border="1" cellspacing="1" cellpadding="2"  align="center" style="width:200px"
{| border="1" cellspacing="1" cellpadding="2"  align="center" style="width:200px"


Line 27: Line 30:
|Time
|Time
|90 min
|90 min
|-
|Elevator
|On
|-
|-
|Substrate
|Substrate
Line 79: Line 79:


<math>X=\frac{(Y\cdot 1000g)}{(1.509g/ml\cdot(0.5-Y))}</math>
<math>X=\frac{(Y\cdot 1000g)}{(1.509g/ml\cdot(0.5-Y))}</math>




Line 111: Line 112:


<math>W_b = W_o - 2d cot(54.7^o) = W_o - \sqrt{2} d</math>
<math>W_b = W_o - 2d cot(54.7^o) = W_o - \sqrt{2} d</math>